SOLUTION: Jeff and Jermaine go ice-skating. Every hour of skating costs each of them $2. A. If Jermaine spends $7.00, how long does she skate for? B. Jeff spends at most $12.00, but also h

Algebra ->  Expressions-with-variables -> SOLUTION: Jeff and Jermaine go ice-skating. Every hour of skating costs each of them $2. A. If Jermaine spends $7.00, how long does she skate for? B. Jeff spends at most $12.00, but also h      Log On


   

Question 167275: Jeff and Jermaine go ice-skating. Every hour of skating costs each of them $2.
A. If Jermaine spends $7.00, how long does she skate for?
B. Jeff spends at most $12.00, but also has to rent skates for $3.50. Write and solve an inequality that determines how long Jeff can skate.
C. How long could they skate together?
D. Write an inequality that would represent how much longer Jeff could skate than Jermaine.
Thank you very much1 Appreciate it!
Answer by Mathtut(3670) About Me  (Show Source):
You can put this solution on YOUR website!
lets call x the number of hours Jeff skates and y the # of hours Jermaine skates
and z is the number of hours they can skate together.
A. 2y=7--->y=3.5 so Jermaine skates for 3.5 hours
B. 2x=12-3.50---->2x=8.5--->x=4.25 so Jeff skates for 4.25 hours
C in this case total number of hours for both we will call z and is at $4/hr
: so 4z=12+7-3.50---->4z=15.50--->z=3.875 so they together could skate for
: 3.875 hours
D not sure how to write the inequality could be x>y if money spent by Jeff is over $7