SOLUTION: At Gwen’s garage sale, all books were one price, and all magazines were another price. Harriet bought four books and three magazines for $1.45, and June bought two books and fiv

Algebra ->  Percentage-and-ratio-word-problems -> SOLUTION: At Gwen’s garage sale, all books were one price, and all magazines were another price. Harriet bought four books and three magazines for $1.45, and June bought two books and fiv      Log On


   

Question 167217: At Gwen’s garage sale, all books
were one price, and all magazines were another price.
Harriet bought four books and three magazines for $1.45,
and June bought two books and five magazines for $1.25.
What was the price of a book and what was the price of a
magazine?
Answer by Mathtut(3670) About Me  (Show Source):
You can put this solution on YOUR website!
so lets call the price per book b and the price per magazine m
so we have 4b%2B3m=1.45
: 2b%2B5m=1.25 multiply bottom equation by -2 and add equations
:
together thus elimiating the b terms
-7m=-1.05 or 7m=1.05 solving for mm=.15
4b%2B3%2815%29=1.45 4b=1.00 b=.25
magazines werehighlight%2815cents%29
books.....werehighlight%2825cents%29