SOLUTION: log base 6 (3x-2) + log base 6 (x-3)=1 i worked out this problem, and got an incorrect answer.

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Question 167210: log base 6 (3x-2) + log base 6 (x-3)=1
i worked out this problem, and got an incorrect answer.
Answer by scott8148(6628) About Me  (Show Source):
You can put this solution on YOUR website!
using rules for logs __ (3x-2)(x-3)=6

3x^2-11x+6=6 __ 3x^2-11x=0 __ x(3x-11)=0

x=0 __ not realistic __ logs are not defined for negative values

3x-11=0 __ x=11/3