SOLUTION: A rock is thrown upward from the ground with an initial velocity of 96 feet per second. The equation giving the height above the ground is h=96t-16t^2, h is the height in feet and
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-> SOLUTION: A rock is thrown upward from the ground with an initial velocity of 96 feet per second. The equation giving the height above the ground is h=96t-16t^2, h is the height in feet and
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Question 167161: A rock is thrown upward from the ground with an initial velocity of 96 feet per second. The equation giving the height above the ground is h=96t-16t^2, h is the height in feet and t is the number of seconds after the rock is thrown.
a. Find the number of seconds when the rock is 80 feet above the ground.
b. Find the number of seconds until the rock hits the ground again. Answer by midwood_trail(310) (Show Source):
You can put this solution on YOUR website! To solve part (a) set equation to 80 and solve for t.
To solve (b), set equation to zero and solve for t.
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