SOLUTION: I have been trying to figure out this math problem and I can't get the answer. I was wondering if someone could help me? Please and Thank You!! I would deeply appreciate it!!
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Question 167137This question is from textbook Algebra and Trigonometry Structure and Method book 2
: I have been trying to figure out this math problem and I can't get the answer. I was wondering if someone could help me? Please and Thank You!! I would deeply appreciate it!!
Problem Solving Using Polynomial Equations
Solve each problem. If there are two correct answers, give both of them.
A rectangle is 15cm wide and 18cm long. If both dimensions are decreased by the same amount, the area of the new rectangle formed is 116cm^2 less than the area of the original. Find the dimensions of the new rectangle. This question is from textbook Algebra and Trigonometry Structure and Method book 2
You can put this solution on YOUR website! A rectangle is 15cm wide and 18cm long. If both dimensions are decreased by the same amount, the area of the new rectangle formed is 116cm^2 less than the area of the original. Find the dimensions of the new rectangle.
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Let x = amount decreased
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new width = 15-x
new length = 18-x
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(15-x)(18-x) = 116
270-15x-18x+x^2 = 116
270-33x+x^2 = 116
154-33x+x^2 = 0
x^2-33x+154 = 0
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Using the quadratic equation to solve we get:
x = {27.374, 5.626}
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We can toss out the 27.374 leaving us with
x = 5.626
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new width = 15-x = 15-5.626 = 9.374 inches
new length = 18-x = 18-5.626 = 12.374 inches
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Solution: new rectangle is 9.374 by 12.374 inches
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Details of quadratic: