SOLUTION: A line passing through(2,3) and (5,y) is perpendicular to a line with a slope 3/4. What is the value of y?

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Question 166991This question is from textbook elementary &intermediate algebra
: A line passing through(2,3) and (5,y) is perpendicular to a line with a slope 3/4. What is the value of y? This question is from textbook elementary &intermediate algebra

Found 2 solutions by nerdybill, jojo14344:
Answer by nerdybill(7384) About Me  (Show Source):
You can put this solution on YOUR website!
.
Use the "point-slope" form of a linear equation:
y-y1 = m(x-x1)
.
For your problem:
(x,y)=(2,3)
(x1,y1)=(5,y)
m = 3/4
.
Plug it in and solve for y:
y-y1 = m(x-x1)
3-y = (3/4)(2-5)
3-y = (3/4)(-3)
12-4y = (3)(-3)
12-4y = -9
12 = 4y-9
21 = 4y
21/4 = y
.

Answer by jojo14344(1513) About Me  (Show Source):
You can put this solution on YOUR website!

(2,3) and (5,y); perpendicular to a line w/ slope=3/4
Via Point-Slope form: m=%28y%5B2%5D-y%5B1%5D%29%2F%28x%5B2%5D-x%5B1%5D%29
But remember, since it's perpendicular, the slope for above points: m%5B2%5D=-1%2Fm%5B1%5D
m%5B2%5D=-1%2F%283%2F4%29=-4%2F3
Subst.,
-4%2F3=%28y%5B2%5D-3%29%2F%285-2%29
-4%2F3=%28y%5B2%5D-3%29%2F3, cross multiply
y%5B2%5D-3=%28-4%2F3%29%283%29=cross%28-12%294%2Fcross%283%29
y%5B2%5D=-4%2B3=-1
highlight%28y%5B2%5D=-1%29, Answer
We'll check the graph but first let's get the y-intercept:
Via Slope-Intercept: y=mx%2Bb
Thru points: (5,-1)
-1=%28-4%2F3%29%285%29%2Bb
-1=%28-20%2F3%29%2Bb
b=%28-1%29%2B%2820%2F3%29=%28-3%2B20%29%2F3 --> b=17%2F3 y intercept
let's see the graph,
--it passes thru points(2,3)(5,-1), see also y-intercept @ (17/3)
Thank you,
Jojo