SOLUTION: how do I solve log(5x-1)=2+log(x-2)

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Question 166958: how do I solve log(5x-1)=2+log(x-2)
Answer by nerdybill(7384) About Me  (Show Source):
You can put this solution on YOUR website!
log(5x-1)=2+log(x-2)
log(5x-1) - log(x-2) = 2
log[(5x-1)/(x-2)] = 2
(5x-1)/(x-2) = 10^2
(5x-1)/(x-2) = 100
(5x-1) = 100(x-2)
5x-1 = 100x-200
199 = 95x
199/95 = x
2.0526 = x