SOLUTION: If car A get's 27 miles to the gallon and car B gets 9 miles to the gallon car A uses 2 gallons to go 54 miles. How many gallons does car B use to go the same distance.
We know
Algebra ->
Proportions
-> SOLUTION: If car A get's 27 miles to the gallon and car B gets 9 miles to the gallon car A uses 2 gallons to go 54 miles. How many gallons does car B use to go the same distance.
We know
Log On
Question 166867: If car A get's 27 miles to the gallon and car B gets 9 miles to the gallon car A uses 2 gallons to go 54 miles. How many gallons does car B use to go the same distance.
We know the answer...just need to know how to write it in proportions. Answer by Mathtut(3670) (Show Source):
You can put this solution on YOUR website! well, logically if you think this out if car B gets 1/3 the mpg that Car A gets then any gas car A uses would mean that car B would uses 3 times that amount
the way you would write this as a proportion is
27mpg*2gal=9mpg*xgal where x is gal used by car B
54=9x and ......how about that 3 times the amount of car A
(