SOLUTION: A bus travels from one town to another at a speed of 42mph. If it had gone 14mph faster, it could have made the trip in a half hour less time. How far apart are the towns?
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Question 166811: A bus travels from one town to another at a speed of 42mph. If it had gone 14mph faster, it could have made the trip in a half hour less time. How far apart are the towns? Answer by ptaylor(2198) (Show Source):
You can put this solution on YOUR website! Distance(d) equals Rate(r) times Time(t) or d=rt; r=d/t and t=d/r
Let d=the distance between the towns
time it takes travellinig at 42 mph=d/42
time it would take travelling 14 mph faster=d/56
Now we are told that if the bus travelled 14 mph faster it could have made the trip in 0.5 hr less time, so our equation to solve is:
(d/42)=d/56+0.5 multiply each term by 504
12d=9d+252 subtract 9d from each side
12d-9d=9d-9d+252 collect like terms
3d=252 divide each side by 3
d=84 mi--------------------------------distance between the two towns
CK
84/42=84/56 + 0.5
2=1.5+0.5
2=2
