SOLUTION: log2(x)+log8(x) = 8
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Question 166799
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log2(x)+log8(x) = 8
Answer by
nerdybill(7384)
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log2(x)+log8(x) = 8
Convert the base:
log(x)/log(2) + log(x)/log(8) = 8
Factor out the log(x):
log(x)[1/log(2) + 1/log(8)] = 8
log(x)[4.429] = 8
log(x) = 1.806
x = 10^1.806
x = 64