SOLUTION: log^2 (x^2-6x) = 3+log^2(1-x)

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Question 166780: log^2 (x^2-6x) = 3+log^2(1-x)
Answer by nerdybill(7384) About Me  (Show Source):
You can put this solution on YOUR website!
I'm assuming when you say log^2, you mean log base 2.
If not, please write back.
.
log2(x^2-6x) = 3+log2(1-x)
log2(x^2-6x) - log2(1-x) = 3
log2[(x^2-6x)/(1-x)] = 3
(x^2-6x)/(1-x) = 2^3
(x^2-6x)/(1-x) = 8
(x^2-6x) = 8(1-x)
x^2-6x = 8-8x
x^2+2x = 8
x^2+2x-8 = 0
(x+4)(x-2) = 0
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x = {-4, 2}