SOLUTION: log(x+8)+ log(x-1)=1 not quite sure how to do this. My guess is to distribute the log then solve for x.

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Question 166760: log(x+8)+ log(x-1)=1
not quite sure how to do this. My guess is to distribute the log then solve for x.
Answer by vleith(2983) About Me  (Show Source):
You can put this solution on YOUR website!
log%28x%2B8%29%2B+log%28x-1%29=1
log%28%28x%2B8%29%28x-1%29%29=1
%28x%2B8%29%28x-1%29=+10%5E1
x%5E2+%2B+7x+-8+=+10
x%5E2+%2B7x+-+18=0
%28x%2B9%29%28x-2%29+=+0
x=-9 or x=2
Sub back into the original equation to find the value(s) that work
Log of a negative number is not defined, so only x=2 works