Question 166621: Please help me with this problem:
Determine the horizontal asymptotes of:
f(x)=2x^2+3/4x^2+5
g(x)=x+4/x^4+2x^4
h(x)=x^5+2/x^3-2
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! Determine the horizontal asymptotes of:
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Procedure:
1st: Find the coefficient of the highest power term whether in the
numerator or in the denominator.
2nd: Form the fraction of the coefficients of that highest power term
as they appear in the numerator and in the denominator.
3rd: The horizontal asumptote is y = that ratio, if it exists.
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f(x)=2x^2+3/4x^2+5
Highest power: x^2
HA: y = 2/4 = 1/2
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g(x)=x+4/x^4+2x^4
Highest power: x^4
HA: y = 0/1 = 0
-----------------------
h(x)=x^5+2/x^3-2
Highest power: x^5
HA: y = 1/0
So, no Horizontal asymptote,
There is a slant asymptote.
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Cheers,
Stan H.
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