SOLUTION: You need 880 mL of a 75% alcohol solution. On hand, you have a 20% alcohol mixture. How much of the 20% alcohol mixture and pure alcohol will you need to obtain the desired solutio
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Question 166588: You need 880 mL of a 75% alcohol solution. On hand, you have a 20% alcohol mixture. How much of the 20% alcohol mixture and pure alcohol will you need to obtain the desired solution?
You will need
mL of the 20% solution
and
mL of pure alcohol. Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! You need 880 mL of a 75% alcohol solution. On hand, you have a 20% alcohol mixture. How much of the 20% alcohol mixture and pure alcohol will you need to obtain the desired solution?
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alcohol + alcohol = alcohol
0.20x + 1(880-x) = 0.75*880
Multiply thru by 100 to get:
20x + 100*880 -100x = 75*880
-80x = - -20*880
x = 220 mml ( amt. of pure alcohol needed for the mixture)
880-220 = 660mml ( amt. of 20% solution you need for the mixture)
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Cheers,
Stan H.
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