SOLUTION: A ball is dropped from a height of 64 feet. Its height above the
earth in feet is given by h(t )= 16t^2+64, where t is the
number of seconds after it is dropped.
a) Find h(1).
Algebra ->
Polynomials-and-rational-expressions
-> SOLUTION: A ball is dropped from a height of 64 feet. Its height above the
earth in feet is given by h(t )= 16t^2+64, where t is the
number of seconds after it is dropped.
a) Find h(1).
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Question 166564This question is from textbook ELEMENTARY AND INTERMEDIATE ALGEBRA
: A ball is dropped from a height of 64 feet. Its height above the
earth in feet is given by h(t )= 16t^2+64, where t is the
number of seconds after it is dropped.
a) Find h(1).
b) How long does it take the ball to fall to the earth? This question is from textbook ELEMENTARY AND INTERMEDIATE ALGEBRA
You can put this solution on YOUR website! Part a:
h(t) = -16t^2 + 64
h(1) = -16(1^2) + 64
h(1) = -16(1) + 64
ANSWER: h(1) = 48 feet
Part b:
The time it takes for the ball to hit the earth is the time from x=0 to the x intercept.
Since h is a function of time h(t), All you need to do is set h=0.
0 = 16t^2 + 64 Now subtract 64 on both sides.
-64 = -16t^2 Now divide both sides by -16.
4 = t^2 Now square root both sides.
2 = t
ANSWER: It takes 2 seconds for the ball to reach the ground.
Note: For you problem to make sense as a math problem, it MUST be -16t^2. This could be a copying error.
Kevin
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