Question 16653: Two numbers, which differ by 3, have a product of 88. Find them by forming a quadratic equation. Answer by rahman(247) (Show Source):
You can put this solution on YOUR website! Suppose: x is the first number and y is the second number.
Math Models:
x - y = 3 ----------->y=x-3 .........(i)
xy=88 .......(ii)
Substitute (i) to (ii)
xy=88
x(x-3)=88
(x+8)(x-11)=0
x+8=0 or x-11=0
x=-8 or x=11
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Substitute x=-8 to (i)
y=x-3
y=-8-3=-11
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Substitute x=11 to (i)
y=x-3
y=11-3=8
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Thus, x=-8 and y=-11 or x=11 and y=8
