SOLUTION: Two cyclists start biking from a trail's start 3 hours apart. The second cyclist travels at 10 miles per hour and starts 3 hours after the first cyclist who is traveling at 6 miles
Algebra ->
Customizable Word Problem Solvers
-> Travel
-> SOLUTION: Two cyclists start biking from a trail's start 3 hours apart. The second cyclist travels at 10 miles per hour and starts 3 hours after the first cyclist who is traveling at 6 miles
Log On
Question 166425: Two cyclists start biking from a trail's start 3 hours apart. The second cyclist travels at 10 miles per hour and starts 3 hours after the first cyclist who is traveling at 6 miles per hour. How much time will pass before the second cyclist catches up with the first from the time the second cyclist started biking? Answer by Mathtut(3670) (Show Source):
You can put this solution on YOUR website!
so lets call d1=r1*T1 1st cyclist T1=T+3 r1=6
.............d2=r2*T2 2nd cyclist T2=T r2=10
:
d1 has to equal d2 since they travel the same distance.
:
equations:
and since:
then:----->
:
2nd cyclist was cycling before he caught the 1st cyclist.
(