SOLUTION: the sum of the squares of six consecutive integers is 1111. what are the integers and what is the problem solving strategy?

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Question 166360: the sum of the squares of six consecutive integers is 1111. what are the integers and what is the problem solving strategy?
Found 2 solutions by jim_thompson5910, Edwin McCravy:
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
Consecutive integers follow the pattern: x, x+1, x+2, x+3...

Since the "sum of the squares of six consecutive integers is 1111", this means that


Now FOIL the expressions to get




and combine like terms to get


6x%5E2%2B30x%2B55=1111


I'll let you solve the equation.


Answer by Edwin McCravy(20060) About Me  (Show Source):
You can put this solution on YOUR website!
the sum of the squares of six consecutive integers is 1111. what are the integers and what is the problem solving strategy?

Let consecutive the integers be x, x%2B1, x%2B2, x%2B3, x%2B4, and x%2B5

Then we have the equation:







Collect terms:

6x%5E2%2B30x%2B55=1111

6x%5E2%2B30x-1056=0
 
Divide through by 6:

x%5E2%2B5x-176=0

Factor:

%28x-11%29%28x%2B16%29=0

Use the zero factor property:

matrix%282%2C3%2Cx-11=0%2C%22%22%2Cx%2B16=0%2Cx=11%2C%22%22%2Cx=-16%29

So there are two solutions:

If x+=+11,  then the consecutive integers are

x, x%2B1, x%2B2, x%2B3, x%2B4, and x%2B5

or

11, 11%2B1, 11%2B2, 11%2B3, 11%2B4, and 11%2B5

or

11, 12, 13, 14, 15, and 16

and if x+=+-16,  then the consecutive integers are

x, x%2B1, x%2B2, x%2B3, x%2B4, and x%2B5

or

-16, -16%2B1, -16%2B2, -16%2B3, -16%2B4, and -16%2B5

or

-16, -15, -14, -13, -12, and -11

Edwin