SOLUTION: I need to know if I can further factor this expression of 27x^3y^3-125 (3xy-5) (9x^2y^2-15xy+25) can you advise me?

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: I need to know if I can further factor this expression of 27x^3y^3-125 (3xy-5) (9x^2y^2-15xy+25) can you advise me?      Log On


   

Question 166349: I need to know if I can further factor this expression of
27x^3y^3-125 (3xy-5) (9x^2y^2-15xy+25) can you advise me?
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
Are you trying to factor 27x%5E3y%5E3-125?


27x%5E3y%5E3-125 Start with the given expression


%283xy%29%5E3-%285%29%5E3 Rewrite 27x%5E3y%5E3 as %283xy%29%5E3 and 125 as %285%29%5E3


A%5E3-B%5E3=%28A-B%29%28A%5E2%2BAB%2BB%5E2%29 Start with Difference of Cubes Formula


%283xy%29%5E3-%285%29%5E3=%283xy-5%29%28%283xy%29%5E2%2B%283xy%29%285%29%2B5%5E2%29 Plug in A=3xy and B=5


%283xy%29%5E3-%285%29%5E3=%283xy-5%29%289x%5E2y%5E2%2B%283xy%29%285%29%2B25%29 Square the values


%283xy%29%5E3-%285%29%5E3=%283xy-5%29%289x%5E2y%5E2%2B15xy%2B25%29 Multiply


So 27x%5E3y%5E3-125 factors to %283xy-5%29%289x%5E2y%5E2%2B15xy%2B25%29.


So the only mistake you made was the sign of the middle term 15xy