SOLUTION: I have a test at my college on monday and I was wondering if you could please explain to me how to solve the equation. 2zx(2)y=18 where x=1,z=y

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Question 166337: I have a test at my college on monday and I was wondering if you could please explain to me how to solve the equation.
2zx(2)y=18 where x=1,z=y

Answer by elima(1433) About Me  (Show Source):
You can put this solution on YOUR website!
I am assuming that (2) is actually an exponent?
2zx(2)y=18 where x=1,z=y
so we rewrite the equation with the information given, we use 1 in place of our x and y in place of z;
2y%281%29%5E2y=18
2y%5E2=18
divide each side by 2;
y%5E2+=+9
take the square root of each side;
sqrt%28y%5E2%29=sqrt%2818%29
we end with;
y=9
Hope this is clear and I helped.
:)