SOLUTION: the sum of two odd integers whose sum is 48

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Question 166269: the sum of two odd integers whose sum is 48
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
Odd integers follow the pattern 2x%2B1, 2x%2B3, etc


So if the "sum of two odd integers whose sum is 48" then %282x%2B1%29%2B%282x%2B3%29=48


4x%2B4=48 Combine like terms on the left side.


4x=48-4 Subtract 4 from both sides.


4x=44 Combine like terms on the right side.


x=%2844%29%2F%284%29 Divide both sides by 4 to isolate x.


x=11 Reduce.


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Answer:

So the answer is x=11 which means that the two numbers are 2%2811%29%2B1=23 and 2%2811%29%2B3=25