SOLUTION: What is the x- and y-intercepts of this equation: 4x + 12y = -18

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Question 166163This question is from textbook Prentice Hall Mathenatics Algebra 1
: What is the x- and y-intercepts of this equation:
4x + 12y = -18 This question is from textbook Prentice Hall Mathenatics Algebra 1

Found 2 solutions by jojo14344, stanbon:
Answer by jojo14344(1513) About Me  (Show Source):
You can put this solution on YOUR website!

4x+%2B+12y+=+-18
Simplify to follow format -----> y=mx%2Bb
12y=-18-4x ----> cross%2812%29y%2Fcross%2812%29=%28-18-4x%29%2F12
y=%28-18%2F12%29-%284x%2F12%29, reduce
y=%28-3%2F2%29-%281%2F3%29%28x%29
Therefore, it has slope=-1%2F3 and y-intercept highlight%28y=-3%2F2%29
f(y)=0:
0=%28-3%2F2%29-%281%2F3%29x
%28-1%2F3%29x=3%2F2 --> cross%28-1%2F3%29x%2Fcross%28-1%2F3%29=%283%2F2%29%2F%28-1%2F3%29
x=%283%2F2%29%28-3%2F1%29
highlight%28x=-9%2F2%29, x intercept.
We'll see in the graph:
--- see points (-9/2,-3/2) --system%28-9%2F2=-4.5%2C-3%2F2=-1.5%29
Thank you,
Jojo

Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
What is the x- and y-intercepts of this equation:
4x + 12y = -18
---------
x-intercept:
Let y=0
Then 4x = -18
x = -9/2
----------
y-intercept:
Let x=0
Then 12y = -18
y = -3/2
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Cheers,
Stan H.