SOLUTION: 10.2 94) Sharing cost: The members of a flying club plan to share equally the cost of $200,000 airplane. The members want to find five more people to join the club so that the cost
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-> SOLUTION: 10.2 94) Sharing cost: The members of a flying club plan to share equally the cost of $200,000 airplane. The members want to find five more people to join the club so that the cost
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Question 166031: 10.2 94) Sharing cost: The members of a flying club plan to share equally the cost of $200,000 airplane. The members want to find five more people to join the club so that the cost per person will decrease by $2000. How many members are currently in the club? Answer by ankor@dixie-net.com(22740) (Show Source):
You can put this solution on YOUR website! The members of a flying club plan to share equally the cost of $200,000 airplane. The members want to find five more people to join the club so that the cost per person will decrease by $2000. How many members are currently in the club?
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Let x = no. of members currently
then
(x+5) = no. of members to reduce the cost/member $2000
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Let's deal in thousands of dollars to lessen the number of zeros we have to write:
: - 2 =
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Multiply equation by x(x+5) to eliminate the denominators, results
200(x+5) - 2x(x+5) = 200x
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200x + 1000 - 2x^2 - 10x = 200x
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Subtract 200x from both sides and we have a quadratic equation
-2x^2 - 10x + 1000
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Simplify and change the signs, divide equation by -2, results
x^2 + 5x - 200 = 0
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Factors easily to:
(x+25)(x-20) = 0
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Positive solution is what we want here:
x = +20 original members
:
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Check solution in original equation
200/20 = 10
200/25 = 8
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differ by 2 (thousand)
