Question 165970: can anyone please help me with this problem:
Use the given table to find the probability of the indicated event. Round your answer to the nearest thousandth.
College students were given three choices of pizza toppings and asked to choose one favorite. The following table shows the results.
toppings; freshman; sophomore; junior; senior
cheese; 10; 12; 24; 21
meat; 22; 21; 12; 10
veggie 12l; 10 22; 21
A randomly selected student prefers a meat topping.
a. .324
b. .0.61
c. .330
d. .185
Answer by jim_thompson5910(35256)   (Show Source):
You can put this solution on YOUR website! In order to find the probability, we need to calculate the totals first. So, for instance, adding up all of the numbers in the freshman column gives us 44, which means that there are 44 freshman. Adding up the number of cheese lovers gives us 67 cheese lovers.
Do this with both the rows AND columns. So you should have a total of 44 freshman, 43 sophomores, 58 juniors, and 52 seniors (these are the totals in the bottom row).
Also, you should have a total of 67 cheese lovers, 65 meat lovers, and 65 veggie lovers (these are the totals in the right-hand column).
So let's add these totals in the table:
toppings freshman sophomore junior senior total
cheese 10 12 24 21 67
meat 22 21 12 10 65
veggie 12 10 22 21 65
total 44 43 58 52 197
Now add up either the totals from the right-hand column or the bottom row to get a total of 197 college students. So 197 college students were sampled.
So the probability of selecting a meat lover is
number of meat lovers 65
P(meat lover) = ------------------------ = ------ = 0.32994
total number of students 197
So rounding to the nearest thousandth, the answer is 0.330 which means that there is a 33% chance of picking a meat lover.
So the answer choice is C) 0.330
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