SOLUTION: Please help me solve this word problem. Three times the width of a certain rectangle exceeds twice its length by three inches, and four times its length is twelve more than its per
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Question 165844: Please help me solve this word problem. Three times the width of a certain rectangle exceeds twice its length by three inches, and four times its length is twelve more than its perimeter. Find the dimensions of the rectangle. Answer by ankor@dixie-net.com(22740) (Show Source):
You can put this solution on YOUR website! Three times the width of a certain rectangle exceeds twice its length by three inches, and four times its length is twelve more than its perimeter. Find the dimensions of the rectangle.
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Take it step-by-step, write an equation each statement:
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"Three times the width of a certain rectangle exceeds twice its length by three inches,"
3W = 2L + 3
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" four times its length is twelve more than its perimeter."
4L = 12 + (2L+2W)
4L = 12 + 2L + 2W
4L - 2L = 12 + 2W
2L = 12 + 2W
Simplify divide by 2
L = W + 6
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In the 1st equation (3W = 2L+3) substitute (W+6) for L
3W = 2(W+6) + 3
3W = 2W + 12 + 3
3W - 2W = 15
W = 15
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Find L
L = 15 + 6
L = 21
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See if this is true in statement:
"Three times the width of a certain rectangle exceeds twice its length by three"
3(15) = 2(21) + 3
45 = 42 + 3
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See if you can prove it in the statement:
"four times its length is twelve more than its perimeter."
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Did the explain it clearly to you? Let me know.
