SOLUTION: roger has $3.10 consisting of quarters, dimes and nickels. He has twice as man quarters as dimes and three more dimes than nickels. find the number of each coin.

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Question 165798: roger has $3.10 consisting of quarters, dimes and nickels. He has twice as man quarters as dimes and three more dimes than nickels. find the number of each coin.
Answer by Mathtut(3670) About Me  (Show Source):
You can put this solution on YOUR website!
q = # of quarters d = # dimes and n = # of nickels
.25q+.1d+.05n=3.10
q=2d
n=d-3
substitute .25%282d%29%2B.1d%2B.05%28d-3%29=3.1
.5d%2B.1d%2B.05d-.15=3.1 combining.65d=3.25 d=5
so q=2%285%29=10 and n=5-3=2
q=10
d=5
n=2