SOLUTION: I am hoping you can help. I have to find an equation of the circle with center {{{matrix( 1,3, "(-2", ",", "3)" ) }}} and radius of {{{sqrt(6)}}}. The formula I am using is {

Algebra ->  Graphs -> SOLUTION: I am hoping you can help. I have to find an equation of the circle with center {{{matrix( 1,3, "(-2", ",", "3)" ) }}} and radius of {{{sqrt(6)}}}. The formula I am using is {      Log On


   

Question 165751: I am hoping you can help. I have to find an equation of the circle with center
matrix%28+1%2C3%2C+%22%28-2%22%2C+%22%2C%22%2C+%223%29%22+%29++ and radius of sqrt%286%29.
The formula I am using is r%5E2=%28x-h%29%5E2%2B%28y-k%29%5E2
I have %28x%2B2%29%5E2%2B%28y-3%29%5E2=36.
Is this correct?
Answer by Edwin McCravy(20055) About Me  (Show Source):
You can put this solution on YOUR website!
I am hoping you can help. I have to find an equation of the circle with center
matrix%28+1%2C3%2C+%22%28-2%22%2C+%22%2C%22%2C+%223%29%22+%29++ and radius of sqrt%286%29.
The formula I am using is r%5E2=%28x-h%29%5E2%2B%28y-k%29%5E2
I have %28x%2B2%29%5E2%2B%28y-3%29%5E2=36.
Is this correct? 


No it isn't. The left side is correct, but the
right side is incorrect.  That's because 

r=sqrt%286%29, and so 

r%5E2=%28sqrt%286%29%29%5E2, or

r%5E2=6, not matrix%281%2C1%2Ccross%28r%5E2=36%29%29 

So the answer should be

%28x%2B2%29%5E2%2B%28y-3%29%5E2=6

Edwin