SOLUTION: We have 20% alcohol solution and a 50% solution. How many pints must be used from each to obtain 8 pints of a 30% solution?

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Question 165518: We have 20% alcohol solution and a 50% solution. How many pints must be used from each to obtain 8 pints of a 30% solution?
Answer by checkley77(12844) About Me  (Show Source):
You can put this solution on YOUR website!
.20x+.50(8-x)=.30*8
.20x+4-.50x=2.4
-.30x=2.4-4
-.30x=-1.6
x=-1.6/-.30
x=5.333 pints of 20% are used.
8-5.333=2.667 pints of 50% are used.
Proof:
.20*5.333+.50*2.667=2.4
1.0666+1.333=2.4
2.4=2.4