Question 165171: Find the equation of the line perpendicular to 3x – 4y = 9 and passing through (-2, -1). Write the equation in standard form, with all integer coefficients.
Answer by Alan3354(69443)   (Show Source):
You can put this solution on YOUR website! Find the equation of the line perpendicular to 3x – 4y = 9 and passing through (-2, -1). Write the equation in standard form, with all integer coefficients.
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1st find the slope of 3x – 4y = 9
Put it into slope-intercept form y = mx + b
3x – 4y = 9
-4y = -3x+9
y = (3/4)x - 9/4
The slope, m, is 3/4. The slope of a line perpendicular is the negative inverse, -4/3.
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Use the slope-intercept eqn:
y-y1 = m(x-x1) where (x1,y1) is the point (-2,-1)
y+1 = (-4/3)*(x+2)
3y+3 = -4x - 8
4x + 3y = -11
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