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Question 165014This question is from textbook
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Find center and radius of the circle x^2 + y^2 - 10x + 2y + 25 = 0.
Let me know if the following below is done wrong. help is appreciated.
x^2 + y^2 - 10x + 2y = -25
(x^2 - 10x)-(y^2 + 2y)= -25
( x^2 -10x -10) -(y^2 + 2y + 1)= -1 - 10 + 1
(x - 2)^5 -(y + 1)^2 = -10
The center is (2,-1); the radius is -2.
This question is from textbook
Answer by Alan3354(69443)   (Show Source):
You can put this solution on YOUR website! Find center and radius of the circle x^2 + y^2 - 10x + 2y + 25 = 0.
Let me know if the following below is done wrong. help is appreciated.
x^2 + y^2 - 10x + 2y = -25
(x^2 - 10x)-(y^2 + 2y)= -25
( x^2 -10x -10) -(y^2 + 2y + 1)= -1 - 10 + 1
(x - 2)^5 -(y + 1)^2 = -10
The center is (2,-1); the radius is -2.
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x^2 + y^2 - 10x + 2y = -25
[x^2 - 10x] + [y^2 + 2y] = -25 (You have a minus sign before y^2)
[x^2 - 10x + 25] + [y^2 + 2y + 1] = -25 + 25 + 1 (25 completes the square, not 10, and you subtracted from the right side, didn't add)
(x-5)^2 + (y+1)^2 = 1
The center is (5,-1) and the radius is 1. (The radius can't be negative.)
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