SOLUTION: 42.) Find b^2 – 4ac and the number of real solutions to each equation. 9m^2+16=24m

Algebra ->  Test -> SOLUTION: 42.) Find b^2 – 4ac and the number of real solutions to each equation. 9m^2+16=24m       Log On


   

Question 164960This question is from textbook Elementary and Intermediate
: 42.) Find b^2 – 4ac and the number of real solutions to each equation.
9m^2+16=24m
 This question is from textbook Elementary and Intermediate

Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
9m%5E2%2B16=24m
9m%5E2-24m%2B16=0
b=-24
a=9
c=16
b%5E2-4ac=%28-24%29%5E2-4%289%29%2816%29=576-576=0
Since b^2-4ac=0, there are two coincident real roots.