SOLUTION: the sum of the ages of two sisters is 37. the difference between four times the older sisters's age and three times the younger sistter's age is 43. how can i find the age of these

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Question 164811: the sum of the ages of two sisters is 37. the difference between four times the older sisters's age and three times the younger sistter's age is 43. how can i find the age of these sisters?
Answer by Mathtut(3670) About Me  (Show Source):
You can put this solution on YOUR website!
lets call the younger sister s1 and the older sister s2. now we know that s1+s2=37 and we know that difference between 4 times the older sisters age which we will write as 4s2 and 3 times the younger sister age which we will write as 3s1 equals 43..writing this out this would be 4s2-3s1=43. So solving for s1 in the 1st equation we get s1=37-s2 plugging that into the second equation we get
4s2-3(37-s2)=43. now multiply out and simplify...we get 7s2=154 divide by 7 and s2=22 so since s1=37-s2(22) we get s1 is 15
answers younger sister 15
older sister 22