SOLUTION: Find four consecutive odd integers whose sum is -80.

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Question 164673: Find four consecutive odd integers whose sum is -80.
Found 2 solutions by Fombitz, Mathtut:
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
Let N be the first odd integer.
The next 3 consecutive integers are N+2, N+4, and N+6.
N%2B%28N%2B2%29%2B%28N%2B4%29%2B%28N%2B6%29=-80
4N%2B12=-80
4N=-92
N=-23
The four integers are then -23,-21,-19,-17.

Answer by Mathtut(3670) About Me  (Show Source):
You can put this solution on YOUR website!
lets first label our integers using variable a. First odd integer we will label a+1. Since they are consecutive we need to add 3,5,and 7 to each of the other integers. we end up with integers a+1,a+3,a+5,and a+7 as being our consecutive integers. Now our equation will be a+1+a+3+a+5+a+7=-80 and simplying we get
4a=-96 which simplifies to a=-24 since a=-24 then a+1=-23 a+3=-21 a+5=-19 and
a+7=-17 so our 4 consecutive negative intergers are -23,-21,-19,-17....checking we get -23+(-21)+(-19)+(-17)= -80