SOLUTION: A jet plane flying with the wind went 2200 miles in 4 hrs. Againt the wind, the plane could fly only 1820 miles in the same amount of time. Find the rate of the plane in calm air a

Algebra ->  Finance -> SOLUTION: A jet plane flying with the wind went 2200 miles in 4 hrs. Againt the wind, the plane could fly only 1820 miles in the same amount of time. Find the rate of the plane in calm air a      Log On


   

Question 164618This question is from textbook
: A jet plane flying with the wind went 2200 miles in 4 hrs. Againt the wind, the plane could fly only 1820 miles in the same amount of time. Find the rate of the plane in calm air and the rate of the wind.

What steps do we use to solve this? This question is from textbook

Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
Rate x Time = Distance
Rate with wind = Speed of Plane in calm air + Speed of Wind=R%5Bw%5D=P%2BW
Rate against wind = Speed of Plane in calm air - Speed of Wind=R%5Ba%5D=P-W
Distance is the same in both cases.
Time with : T%5Bw%5D=4
Time against : T%5Ba%5D=4
Distance with : D%5Bw%5D=2200
Distance against : D%5Ba%5D=1820
Generate your two rate equations (R%5Bw%5DT%5Bw%5D=D%5Bw%5D and R%5Ba%5DT%5Ba%5D=D%5Ba%5D) in terms of P and W and the known quantitites.
Solve for P and W.