SOLUTION: Find a three digit number whose tens digit is 4 times the hundred’s digit and the unit’s digit is one more than the ten’s digit. The square of the sum of the digits is 72 more than
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Question 164607: Find a three digit number whose tens digit is 4 times the hundred’s digit and the unit’s digit is one more than the ten’s digit. The square of the sum of the digits is 72 more than the number? Answer by vleith(2983) (Show Source):
You can put this solution on YOUR website! Let H be the hundred digit.
Then the tens digit is 4H
The ones digit is 4H+1
The "number is (H*100)+(4H*10)+(4H+1) = (100H)+(40H)+(4H+1)= 144H + 1
The sum of the digits is H+4H+4H+1 = 9H+1
You are told the square of the sum of the digits is 72 more than the number itself
So }
H = -4/9 or 18/9=2
Since the number is an integer, the answer must be H=4
Test your answer. Does
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