SOLUTION: solve for the zeros or roots of this polynomial equation
r(x)= (x-7)^2 times (x^2+7)
Please Please explain step by step because I really want to learn how to solve for the ze
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-> SOLUTION: solve for the zeros or roots of this polynomial equation
r(x)= (x-7)^2 times (x^2+7)
Please Please explain step by step because I really want to learn how to solve for the ze
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Question 164565: solve for the zeros or roots of this polynomial equation
r(x)= (x-7)^2 times (x^2+7)
Please Please explain step by step because I really want to learn how to solve for the zeros of polynomial equations. Thank you for any help. Please Help Soon! Answer by jim_thompson5910(35256) (Show Source):
You can put this solution on YOUR website! "Zeros" or "roots" are simply math speak for values of x that make the ENTIRE equation equal to zero (note: "zeros" are not necessarily equal to zero)
So this means that we set the right side equal to zero like this:
or Use the zero product property to break up the factors
Let's solve the first equation:
Start with the given equation
Take the square root of both sides to eliminate the square on the left side.
Add 7 to both sides.
So the first solution is
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Now let's solve the second equation:
Start with the given equation
Subtract 7 from both sides.
Take the square root of both sides.
Since you CANNOT take the square root of a negative number, this means:
a) there are NO real solutions (for this part), and
b) there are two complex (ie imaginary) solutions (if you have never heard of complex/imaginary solutions, then just ignore this next part)
So the two complex imaginary solutions are or
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Answer:
So the solution(s) are
, or
Ignore the last two solutions if you have never heard of complex/imaginary solutions before.