SOLUTION: (4x-3)/6 + (x/4) = x-2 I've been struggling with this problem and I'd love it if you would help me. I'd appreciate it very very much! Thanks for your consideration! I've never b

Algebra ->  Trigonometry-basics -> SOLUTION: (4x-3)/6 + (x/4) = x-2 I've been struggling with this problem and I'd love it if you would help me. I'd appreciate it very very much! Thanks for your consideration! I've never b      Log On


   



Question 164495: (4x-3)/6 + (x/4) = x-2
I've been struggling with this problem and I'd love it if you would help me. I'd appreciate it very very much! Thanks for your consideration! I've never been good at fractions like this...

Answer by nerdybill(7384) About Me  (Show Source):
You can put this solution on YOUR website!
Multiply both sides by a common denominator (say 24) to get rid of all denominators.
.
(4x-3)/6 + (x/4) = x-2
24[(4x-3)/6 + (x/4)] = 24[x-2]
4(4x-3) + 6(x) = 24[x-2]
16x - 12 + 6x = 24x - 48
18x - 12 = 24x - 48
- 12 = 6x - 48
36 = 6x
6 = x