SOLUTION: Fifty gallons of a 90% alcohol solution is obtained by mixing a 100% solution with a 75% solution. How many gallons of each solution must be used to obtain the desired mixture?
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Question 164480: Fifty gallons of a 90% alcohol solution is obtained by mixing a 100% solution with a 75% solution. How many gallons of each solution must be used to obtain the desired mixture? Answer by checkley77(12844) (Show Source):
You can put this solution on YOUR website! X+.75(5-X)=.9*5
X+3.75-.75X=4.5
.25X=4.5-3.75
.25X=.75
X=.75/.25
X=3 GALLONS OD 100% SOLUTION.
PROOF:
3+.75(5-3)=.9*5
3+.75*2=4.5
3+1.5=4.5
4.5=4.5
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