SOLUTION: Fine an equation of the line containing the two given points. (1,16) and (-2,-16) I got -16-16=-32 and -2-1=-3 so -32 -3

Algebra ->  Graphs -> SOLUTION: Fine an equation of the line containing the two given points. (1,16) and (-2,-16) I got -16-16=-32 and -2-1=-3 so -32 -3      Log On


   

Question 164448: Fine an equation of the line containing the two given points.
(1,16) and (-2,-16)
I got -16-16=-32 and -2-1=-3 so -32
-3
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!

First let's find the slope of the line through the points and


m=%28y%5B2%5D-y%5B1%5D%29%2F%28x%5B2%5D-x%5B1%5D%29 Start with the slope formula.


m=%28-16-16%29%2F%28-2-1%29 Plug in y%5B2%5D=-16, y%5B1%5D=16, x%5B2%5D=-2, and x%5B1%5D=1


m=%28-32%29%2F%28-2-1%29 Subtract 16 from -16 to get -32


m=%28-32%29%2F%28-3%29 Subtract 1 from -2 to get -3


m=32%2F3 Reduce


So the slope of the line that goes through the points and is m=32%2F3


Now let's use the point slope formula:


y-y%5B1%5D=m%28x-x%5B1%5D%29 Start with the point slope formula


y-16=%2832%2F3%29%28x-1%29 Plug in m=32%2F3, x%5B1%5D=1, and y%5B1%5D=16


y-16=%2832%2F3%29x%2B%2832%2F3%29%28-1%29 Distribute


y-16=%2832%2F3%29x-32%2F3 Multiply


y=%2832%2F3%29x-32%2F3%2B16 Add 16 to both sides.


y=%2832%2F3%29x%2B16%2F3 Combine like terms. note: If you need help with fractions, check out this solver.


y=%2832%2F3%29x%2B16%2F3 Simplify


So the equation that goes through the points and is y=%2832%2F3%29x%2B16%2F3