SOLUTION: I need help with this question as soon as possible. I have been working on it and cannot figure it out.
The weight of an object follows this equation: {{{w=Cr^-2}}} where C is
Algebra ->
Radicals
-> SOLUTION: I need help with this question as soon as possible. I have been working on it and cannot figure it out.
The weight of an object follows this equation: {{{w=Cr^-2}}} where C is
Log On
Question 164387: I need help with this question as soon as possible. I have been working on it and cannot figure it out.
The weight of an object follows this equation: where C is the constant, r is the distance from the center of the earth (3963 miles). Using the value of C = 1570536900, determine how much an object would weigh in Death Valley (282 feet below sea level).
How much would the object weigh at the top of Mt. McKinley (20,320 feet above sea level).
Thank you! Answer by josmiceli(19441) (Show Source):
You can put this solution on YOUR website! It looks like is from the center of the Earth to sea level,
so the distance from Death Valley to the center of the Earth (in miles)
would be mi
The distance from the Earth's center to the top of Mt Mckinley
in miles would be mi
I got these heights in miles because the equation uses miles
For Death Valley:
For Mt McKinley:
