SOLUTION: I need help with this question as soon as possible. I have been working on it and cannot figure it out. The weight of an object follows this equation: {{{w=Cr^-2}}} where C is

Algebra ->  Radicals -> SOLUTION: I need help with this question as soon as possible. I have been working on it and cannot figure it out. The weight of an object follows this equation: {{{w=Cr^-2}}} where C is      Log On


   

Question 164386: I need help with this question as soon as possible. I have been working on it and cannot figure it out.
The weight of an object follows this equation: w=Cr%5E-2 where C is the constant, r is the distance from the center of the earth (3963 miles). Using the value of C = 1570536900, determine how much an object would weigh in Death Valley (282 feet below sea level).
Thank you!
Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
You can put this solution on YOUR website!
The weight of an object follows this equation: w=Cr%5E-2 where C is the constant, r is the distance from the center of the earth (3963 miles). Using the value of C = 1570536900, determine how much an object would weigh in Death Valley (282 feet below sea level).
:
since we have the radius in miles we have to convert 282 ft to mile:
282%2F5280 = .05341 mi below sea level:
w=Cr%5E-2
the reciprocal of r will take care of the neg exponent
w=C%2Fr%5E2
Substitute for C and r, subtract the dist below sealevel
w=1570536900%2F%28%283963-.05341%29%5E2%29
w=1570536900%2F%28%283962.94659%29%5E2%29
w=1570536900%2F15704940.21
w = 100.00273 lb; Means 100 lb weight in death valley is slightly heavier
:
A lot numbers to crunch here. Check my math on your calc.