SOLUTION: expresss log2 (2x-1)=5 in expotential form

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Question 164357: expresss log2 (2x-1)=5 in expotential form
Answer by Alan3354(69443) About Me  (Show Source):
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expresss log2 (2x-1)=5 in expotential form
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2^log(2x-1) = 2^5
2x-1 = 2^5 (exponential form)
2x-1 = 32
2x = 33
x = 16.5