SOLUTION: Please help me solve this problem. I do not understanding the problem at all. A forester mixes gasoline and oil to make 2 gallons of mixture for his two-cycle chain-saw engi

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Question 164348This question is from textbook Algebra and Trigonometry
: Please help me solve this problem. I do not understanding the problem at all.
A forester mixes gasoline and oil to make 2 gallons of mixture for his two-cycle chain-saw engine. This mixture is 32 parts gasoline and 1 part two-cycle oil. How much gasoline must be added to bring the mixture to 40 parts gasoline and 1 part oil? This question is from textbook Algebra and Trigonometry

Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
You can put this solution on YOUR website!
A forester mixes gasoline and oil to make 2 gallons of mixture for his two-cycle chain-saw engine. This mixture is 32 parts gasoline and 1 part two-cycle oil. How much gasoline must be added to bring the mixture to 40 parts gasoline and 1 part oil?
:
Convert the mixtures to percent oil (decimal equiv):
1%2F%28%2832%2B1%29%29 = .0303
1%2F%28%2840%2B1%29%29 = .0244
:
Let x = amt of gas added to make the 40:1 mixture
:
Write an amt of oil equation, (amt of oil remains the same, only the % changes)
.0303(2) = .0244(2+x)
.0606 = .0488 + .0244x
.0606 - .0488 = .0244x
.0118 = .0244x
x = .0118%2F.0244
x = .4836 gal of gas to be added