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Question 164191: Suppose you are at the gas station filling your tank with gas. The function C(g) represents the cost C of filling up the gas tank with g gallons. Given the equation: C(g)=3.03(g)
Find C(2)
Find C(9)
I have solved as...
C(2)=3.03(g)
C*2-3.03*g=0
is this correct?
C(9)...
C(9)=3.03(g)
c*9-3.03*g=0
Is this correct?
Found 2 solutions by aka042, marcsam823:
Answer by aka042(26)   (Show Source):
You can put this solution on YOUR website! Hi-
Whenever we are given a function C(g) and g = some number n, this means that we plug the number n wherever g appears in the equation.
So for your first problem, find C(2), we simply plug 2 into the C(g) equation whereever g is. Since C(g) = 3.03*g, then C(2) = 3.03*2 = 6.06. So C(2) = 6.06.
For the next problem, C(9) we plug 9 into g to get C(9) = 3.03 * 9 = 27.27. So C(9) = 27.27
I think you may be confusing C(g) to mean C * g. Note that when we are writing a function C(g), then C(g) is said C OF g, not C times 6. It may be a little confusing, but C is actually the name of the function, not a variable. So you don't multiply C with anything!
Answer by marcsam823(57) (Show Source):
You can put this solution on YOUR website! The problem that is presented here is asking you to determine the total cost of the gasoline by plugging in a value for the given variable: number of gallons (g).
When you see a problem in the form:
C(g) = 3.03 * g
The left side of the problem represents the notation for a function. In this function you are asked to calculate the total cost of 2 gallons of gas and 9 gallons of gas if the cost per gallon is $3.03.
In other words calculate for g = 2 and g = 9.
Problem 1:
C(2) = 3.03 * 2
C(2) = 6.06
Problem 2:
C(9) = 3.03 * 9
C(9) = 27.27
The number in the parentheses is simply a convenient place to store the value for "g" while you are plugging into the right hand side of th equation. No need to add or subtract it!
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