SOLUTION: 1) The lesser of tow consecutive even integers is 10 more than one-half the greater. Find the integers.
2) The greater of two consecutive even integers is 6 less than the times
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-> SOLUTION: 1) The lesser of tow consecutive even integers is 10 more than one-half the greater. Find the integers.
2) The greater of two consecutive even integers is 6 less than the times
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Question 164180: 1) The lesser of tow consecutive even integers is 10 more than one-half the greater. Find the integers.
2) The greater of two consecutive even integers is 6 less than the times the lesser. Find the integers.
3) Find four consecutive integers such that twice the sum of the two greater integers exceeds three times the first by 91
4) Find a set of four consecutive positive integers such that the greatest integer in the set is twice the least integer in the set. Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! 1) The lesser of two consecutive even integers is 10 more than one-half the greater. Find the integers.
1st: 2x
2nd: 2x+2
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EQUATION:
2x =(1/2)(2x+2)+10
2x = x + 11
x = 11
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1st: 2x = 22
2nd: 2x + 2 = 24
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2) The greater of two consecutive even integers is 6 less than the times the lesser. Find the integers.
I'll leave this to you. Something is missing is the statement of the problem.
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3) Find four consecutive integers such that twice the sum of the two greater integers exceeds three times the first by 91.
1st: x
2nd: x+1
3rd: x+2
4th: x+3
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EQUATION:
2(x+2 + x+3) = 3x + 91
4x + 12 = 3x + 91
x = 79
x+1 = 80
etc.
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4) Find a set of four consecutive positive integers such that the greatest integer in the set is twice the least integer in the
I'll leave this to you.
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Cheers,
Stan H.
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