SOLUTION: $1.65 is made up of pennies, nickels, and dimes. Half of the coins are nickels. List a set of coins that will solve the problem including why only the set of coins you chose worked

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Question 164168: $1.65 is made up of pennies, nickels, and dimes. Half of the coins are nickels. List a set of coins that will solve the problem including why only the set of coins you chose worked in this situation. Remember you are communication information to some one who may have no idea what you are talking about, so the more information you give, the better off you will be. Use proper grammar and complete sentences in your explanation
Answer by Edwin McCravy(20060) About Me  (Show Source):
You can put this solution on YOUR website!


I'll just work the problem for you. You'll have to
write it up using complete sentences and proper grammar,
and filling in your own explanations.

Let p = the number of pennies
Let n = the number of nickels
Let d = the number of dimes

We have the equation:

.01p+%2B+.05n+%2B+.10d+=+1.65

or multiplying through by 100,

p%2B5n%2B10d=165

Since half the coins are nickels, we have

n+=+%28p%2Bn%2Bd%29%2F2

2n+=+p%2Bn%2Bd

n=p%2Bd 

We have the system:

system%28p+%2B+5n+%2B+10d+=+165%2Cn=p%2Bd%29

Substituting p%2Bd for n in the first equation

p+%2B+5%28p%2Bd%29+%2B+10d+=+165

p+%2B+5p%2B5d+%2B+10d+=+165

6p+%2B+15d+=+165

Divide through by 3:

2p+%2B+5d+=+55

2p+=+55-5d

2p+=+5%2811-d%29

Since the left side is even,
the right side must be even also,
and positive. Therefore 11-d 
must be even and positive, too, 
Therefore d must be odd and no more 
than 11.

Therefore there are 6 possibilities:

d = 1, 3, 5, 7, 9, or 11

If d=1, then

2p+=+5%2811-d%29 becomes
2p+=+5%2811-1%29
2p+=+5%2810%29
2p+=+50
p+=+25

Substituting d=1 and p=25
into

p+%2B+5n+%2B+10d+=+165
25+%2B+5n+%2B+10%281%29+=+165
25+%2B+5n+%2B+10+=+165
35+%2B+5n+=+165
5n+=+130
n+=+26

So one possibility is 

p=25, n=26, d=1

-------

If d=3, then

2p+=+5%2811-d%29 becomes
2p+=+5%2811-3%29
2p+=+5%288%29
2p+=+40
p+=+20

Substituting d=3 and p=20
into

p+%2B+5n+%2B+10d+=+165
20+%2B+5n+%2B+10%283%29+=+165
20+%2B+5n+%2B+30+=+165
50+%2B+5n+=+165
5n+=+115
n+=+23

So another possibility is 

p=20, n=23, d=3

-----------------

If d=5, then

2p+=+5%2811-d%29 becomes
2p+=+5%2811-5%29
2p+=+5%286%29
2p+=+30
p+=+15

Substituting d=5 and p=15
into

p+%2B+5n+%2B+10d+=+165
15+%2B+5n+%2B+10%285%29+=+165
15+%2B+5n+%2B+50+=+165
65+%2B+5n+=+165
5n+=+100
n+=+20

So another possibility is 

p=15, n=20, d=5

-------------

If d=7, then

2p+=+5%2811-d%29 becomes
2p+=+5%2811-7%29
2p+=+5%284%29
2p+=+20
p+=+10

Substituting d=7 and p=10
into

p+%2B+5n+%2B+10d+=+165
10+%2B+5n+%2B+10%287%29+=+165
10+%2B+5n+%2B+70+=+165
80+%2B+5n+=+165
5n+=+85
n+=+17

So another possibility is 

p=10, n=17, d=7

-------------

If d=9, then

2p+=+5%2811-d%29 becomes
2p+=+5%2811-9%29
2p+=+5%282%29
2p+=+10
p+=+5

Substituting d=9 and p=5
into

p+%2B+5n+%2B+10d+=+165
5+%2B+5n+%2B+10%289%29+=+165
5+%2B+5n+%2B+90+=+165
95+%2B+5n+=+165
5n+=+70
n+=+14

So another possibility is 

p=5, n=14, d=9

-------------

If d=11, then

2p+=+5%2811-d%29 becomes
2p+=+5%2811-11%29
2p+=+5%280%29
2p+=+0
p+=+0

Substituting d=11 and p=0
into

p+%2B+5n+%2B+10d+=+165
0+%2B+5n+%2B+10%2811%29+=+165
0+%2B+5n+%2B+110+=+165
5n+=+55
n+=+11

So another possibility is 

p=0, n=11, d=11

-------------

So all the 6 possibilities are 

0 pennies, 11 nickels, 11 dimes, 22 coins, half of which are 11 nickels.
5 pennies, 14 nickels, 9 dimes, 28 coins, half of which are 14 nickels.
10 pennies, 17 nickels, 7 dimes, 34 coins, half of which are 17 nickels.
15 pennies, 20 nickels, 5 dimes, 40 coins, half of which are 20 nickels.
20 pennies, 23 nickels, 3 dimes, 46 coins, half of which are 23 nickels.
25 pennies, 26 nickels, 1 dimes, 52 coins, half of which are 26 nickels.

Edwin