SOLUTION: How many pounds of candy selling for $2 a pound should be added to three pounds of candy selling for $3.75 a pound to create a blend, which will sell for $2.75 a pound. Is it ri

Algebra ->  Customizable Word Problem Solvers  -> Misc -> SOLUTION: How many pounds of candy selling for $2 a pound should be added to three pounds of candy selling for $3.75 a pound to create a blend, which will sell for $2.75 a pound. Is it ri      Log On

Ad: Over 600 Algebra Word Problems at edhelper.com


    

Question 164124: How many pounds of candy selling for $2 a pound should be added to three pounds of candy selling for $3.75 a pound to create a blend, which will sell for $2.75 a pound.
Is it right?????
"C for the unknown candy"
3(3.75) + 2.75 = 2C
11.25 + 2.75 = 2C
14 = 2C
******
7 = C
******
Found 2 solutions by checkley77, scott8148:
Answer by checkley77(12844) About Me  (Show Source):
You can put this solution on YOUR website!
2x+3*3.75=(3+x)*2.75
2x+11.25=8.25+2.75x
2x-2.75x=8.25-11.25
-.75x=-3
x=-3/-.75
x=4 pounds of the $2 candy is used.
PROOF"
2*4+11.25=8.25+2.75*4
8+11.25=8.25+11
19.25=19.25

Answer by scott8148(6628) About Me  (Show Source):
You can put this solution on YOUR website!
"How many pounds of candy selling for $2 a pound" __ 2C

"should be added to" __ +

"three pounds of candy selling for $3.75 a pound" __ 3(3.75)

"to create a blend, which will sell for $2.75 a pound" __ =(3+C)(2.75)

2C+11.25=8.25+2.75C __ 3=.75C __ 4=C