SOLUTION: Solve the following algebraically. Trial and error is not an appropriate method of solution. {{{matrix(2,3,"", "","",x^(3/2), "=",125 )}}}

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: Solve the following algebraically. Trial and error is not an appropriate method of solution. {{{matrix(2,3,"", "","",x^(3/2), "=",125 )}}}      Log On


   



Question 164116This question is from textbook
: Solve the following algebraically. Trial and error is not an appropriate method of solution. matrix%282%2C3%2C%22%22%2C+%22%22%2C%22%22%2Cx%5E%283%2F2%29%2C+%22=%22%2C125+%29 This question is from textbook

Answer by Edwin McCravy(20056) About Me  (Show Source):
You can put this solution on YOUR website!

 matrix%282%2C3%2C%22%22%2C+%22%22%2C%22%22%2Cx%5E%283%2F2%29%2C+%22=%22%2C125+%29

Raise both sides to the power which is the reciprocal
of 3%2F2 power, which is the 2%2F3 power:



Multiply the exponents on the left to remove the
parentheses:



Cancel:



The exponent on the left becomes 1

matrix%282%2C3%2C%22%22%2C%22%22%2C%22%22%2C+x%5E1%2C%22=%22%2C125%5E%282%2F3%29%29

and we can drop the 1 exponent:

matrix%282%2C3%2C%22%22%2C%22%22%2C%22%22%2C+x%2C%22=%22%2C125%5E%282%2F3%29%29

Use this rule for the right side:  

matrix%282%2C3%2C%22%22%2C%22%22%2C%22%22%2C+x%2C%22=%22%2C%28root%283%2C125%29%29%5E2+++%29

Since 125=5%2A5%2A5=5%5E3, root%283%2C125%29=5, so we have:

matrix%282%2C3%2C%22%22%2C%22%22%2C%22%22%2C+x%2C%22=%22%2C%285%29%5E2+++%29

matrix%282%2C3%2C%22%22%2C%22%22%2C%22%22%2C+x%2C%22=%22%2C25+++%29

Edwin