Question 164095: the product of two consecutive even integers is 168 Found 3 solutions by elima, EthanT.Terrell, MathTherapy:Answer by elima(1433) (Show Source):
You can put this solution on YOUR website! 1st integer = x
2nd integer = x+2
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x(x+2)=168
(x+14)(x-12)=0
x+14=0
x=-14
x-12=0
x=12
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So we end up with 2 possibilities;
x = 12 or x = -14
Now we need our second;
x + 2 = 12+2=14
x+2 = -14+2=-12
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When x = 12, the second integer = 14
When x = -14, second integer = -12
:)
You can put this solution on YOUR website! x(x+2)=168
x^2+2x=168
-168 -168
x^2+1x-168=0
(x+14)(x-12)
x+14=0 or x-12=0_
x=-14 X=12
-14 reflects to 14
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Solutions= 14, 12
Since the product of the integers is 168, then we'll have: F(F + 2) = 168
(F + 14)(F - 12) = 0
F = - 14 or 12
If the 1st even integer is - 14, then the second consecutive even integer is - 12. Or, if the 1st even integer is 12, then the second consecutive even integer is 14.
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