SOLUTION: Given three consecutive integers. When half the secondinteger is subtracted from twice the first one the result is eleven less than the third one. Find the three integers.
Algebra ->
Customizable Word Problem Solvers
-> Numbers
-> SOLUTION: Given three consecutive integers. When half the secondinteger is subtracted from twice the first one the result is eleven less than the third one. Find the three integers.
Log On
Question 164091: Given three consecutive integers. When half the secondinteger is subtracted from twice the first one the result is eleven less than the third one. Find the three integers. Answer by checkley77(12844) (Show Source):
You can put this solution on YOUR website! Let x, x+1 & x+2 be the 3 integers.
2x-(x+1)/2=(x+2)-11
2x-x/2-1/2=x+2-11
3x/2-x=-9+1/2
x/2=-17/2
x=-17 Answer for the smallest integer.
-17+1=-16 for the middle integer.
-17+2=-15 for the larger integer..
Proof:
2*-17-(-16/2)=-15-11
-34-(-8)=-26
-34+6=-26
-26=-26
(